Python与Java数据结构语法区别

LTQ'blog / 2024-04-20 / 原文

数组

参考链接：CS61B

Python

zeroedLst = [0, 0, 0]

lst = [4, 7, 10]

lst[0] = 5

print(lst[0])

print(lst)

print(len(lst))

Java

int[] zeroedArray = new int[3];

int[] array = {4, 7, 10};

array[0] = 5;

System.out.println(array[0]);

System.out.println(Arrays.toString(array));

System.out.println(array.length)

# 循环

Python	Java
lst = [1, 2, 3] for i in lst: print(i)	int[] array = {1, 2, 3}; for (int i : array) { System.out.println(i); }

lst = [1, 2, 3]

for i in lst:

print(i)

int[] array = {1, 2, 3};

for (int i : array) {

System.out.println(i);

}

# 列表(可调整大小)

Python	Java
lst = [] lst.append("zero") lst.append("one") lst[0] = "zed" print(l[0]) print(len(l)) if "one" in lst: print("one in lst") for elem in lst: print(elem)	List<String> lst = new ArrayList<>(); lst.add("zero"); lst.add("one"); lst.set(0, "zed"); System.out.println(lst.get(0)); System.out.println(lst.size()); if (lst.contains("one")) { System.out.println("one in lst"); } for (String elem : lst) { System.out.println(elem); }

lst = []

lst.append("zero")

lst.append("one")

lst[0] = "zed"

print(l[0])

print(len(l))

if "one" in lst:

print("one in lst")

for elem in lst:

print(elem)

List<String> lst = new ArrayList<>();

lst.add("zero");

lst.add("one");

lst.set(0, "zed");

System.out.println(lst.get(0));

System.out.println(lst.size());

if (lst.contains("one")) {

System.out.println("one in lst");

}

for (String elem : lst) {

System.out.println(elem);

}

集合

Python	Java
s = set() s.add(1) s.add(1) s.add(2) s.remove(2) print(len(s)) if 1 in s: print("1 in s") for elem in s: print(elem)	Set<Integer> set = new HashSet<>(); set.add(1); set.add(1); set.add(2); set.remove(2); System.out.println(set.size()); if (set.contains(1)) { System.out.println("1 in set"); } for (int elem : set) { System.out.println(elem); }

s = set()

s.add(1)

s.add(2)

s.remove(2)

print(len(s))

if 1 in s:

print("1 in s")

for elem in s:

print(elem)

Set<Integer> set = new HashSet<>();

set.add(1);

set.add(2);