例题2.13

DENWOSHUABAZONGSHI / 2024-11-11 / 原文

例题2.13代码

def bifurcate_by(L, fn):
    return [[x for x in L if fn(x)], [x for x in L if not fn(x)]]
s = bifurcate_by(['beep', 'boop', 'foo', 'bar'], lambda x: x[0] == 'b')
print(s)