例题2.23
例题2.23代码
def filter_non_unique(L):
return [item for item in L if L.count(item) == 1]
a = filter_non_unique([1, 2, 3, 4, 5])
print(a)
def filter_non_unique(L):
return [item for item in L if L.count(item) == 1]
a = filter_non_unique([1, 2, 3, 4, 5])
print(a)