[Python手撕]不同的二叉搜索树

THINK TWICE, CODE ONCE. / 2024-10-06 / 原文

class Solution:
    def numTrees(self, n: int) -> int:
        dp = [0]*(n+1)
        dp[0] = 1
        dp[1] = 1
        for i in range(2,n+1):
            for j in range(i):
                dp[i] += dp[j]*dp[i-1-j]
        return dp[-1]