2024/08/29 每日一题

XuGui / 2024-08-31 / 原文

LeetCode 3142 判断矩阵是否满足条件

方法1:模拟

class Solution {
    public boolean satisfiesConditions(int[][] grid) {
        int n = grid.length, m = grid[0].length;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (i < n - 1 && grid[i][j] != grid[i + 1][j])
                    return false;
                if (j < m - 1 && grid[i][j] == grid[i][j + 1])
                    return false;
            }
        }
        return true;
    }
}