题目

Harper886’s Blog / 2023-05-04 / 原文

P1387 最大正方形

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <vector>
#include <cstring>
#include <unordered_set>
#include <set>
#include <stack>
#include <map>
#include <cmath>
#include <sstream>
#include <queue>
#define int long long
#define yes cout<<"YES"<<'\n'
#define no 	cout<<"NO"<<'\n'

using namespace std;

signed main () {
	int n, m;
	int a[110][110] = {0};
	int dp[110][110] = {0};
	scanf("%lld %lld", &n, &m);
	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= m; j++) {
			scanf("%lld", &a[i][j]);
		}
	}
	int mmax = 0;
	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= m; j++) {
			if (a[i][j] == 0) {
				dp[i][j] = 0;
			} else {

				dp[i][j] = min(min(dp[i - 1][j - 1], dp[i - 1][j]), dp[i][j - 1]) + 1;

			}
			mmax = max(mmax, dp[i][j]);
		}
	}

	printf("%lld\n", mmax);


	return 0;
}

采药

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <vector>
#include <cstring>
#include <unordered_set>
#include <set>
#include <stack>
#include <map>
#include <cmath>
#include <sstream>
#include <queue>
#define int long long
#define yes cout<<"YES"<<'\n'
#define no 	cout<<"NO"<<'\n'

using namespace std;
const int N = 1003;
int n, m;
int t[N];
int v[N];
int f1[1002];
int f2[1002];
signed main () {

	cin >> n >> m;
	for (int i = 1; i <= m; i++) {
		scanf("%lld %lld", &t[i], &v[i]);
	}
	for (int i = 1; i <= m; i++) {
		for (int j = 0; j <= n; j++) {
			if (j >= t[i]) {
				f2[j] = max(f1[j - t[i]] + v[i], f1[j]);
			} else {
				f2[j] = f1[j];

			}

		}
		memcpy(f1, f2, sizeof(f1));//滚动数组优化
	}
	cout << f1[n] << '\n';//打印结果




	return 0;
}

数字三角形

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <vector>
#include <cstring>
#include <unordered_set>
#include <set>
#include <stack>
#include <map>
#include <cmath>
#include <sstream>
#include <queue>
//#define int long long
#define yes cout<<"YES"<<'\n'
#define no 	cout<<"NO"<<'\n'

using namespace std;
const int N = 1002;



int main () {
	int a[N][N] = {0};
	int dp[N][N] = {0};
	int n;
//	while (1) {
	scanf("%d", &n);

	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= i; j++) {
			scanf("%d", &a[i][j]);
		}
	}
	for (int j = 1; j <= n; j++) {
		dp[n][j] = a[n][j];
//			cout<<dp[n][j]<<' ';
	}
//		cout<<'\n';

	for (int i = n - 1; i >= 1; i--) {
		for (int j = 1; j <= i; j++) {
			dp[i][j] = max(dp[i + 1][j], dp[i + 1][j + 1]) + a[i][j];
		}
	}
//			for(int i=1;i<=n;i++){
//					for(int j=1;j<=i;j++){
//					cout<<dp[i][j]<<' ';
//					}
//					cout<<'\n';
//
//				}

	printf("%d\n", dp[1][1]);

//	}



	return 0;
}