0-1BFS(双端队列BFS)
OIWIKI上面的解释
[ABC176D] Wizard in Maze------------------------------------------------------模板题

#include<bits/stdc++.h>
using namespace std;
#define endl "\n"
typedef long long ll;
const int N = 1e3 + 5;
struct Node{
int x, y;
};
deque<Node>q;
int n, m, ex, ey, sx, sy, dist[N][N];
int dir[4][2]={1,0,0,1,-1,0,0,-1};
char a[N][N];
void bfs(){
q.push_back({sx, sy});
dist[sx][sy] = 0;
while(!q.empty()){
auto [x, y] = q.front();
q.pop_front();
int now = dist[x][y];
for(int i = 0 ; i < 4; i++){
int nx = x + dir[i][0];
int ny = y + dir[i][1];
if(nx >= 1 && nx <= n && ny >= 1 && ny <= m && a[nx][ny] != '#'){
if(now < dist[nx][ny]){
dist[nx][ny] = now;
q.push_front({nx, ny});
}
}
}
for(int i = -2; i <= 2; i++){
for(int j = -2; j <= 2; j++){
int nx = x + i;
int ny = y + j;
if(nx >= 1 && nx <= n && ny >= 1 && ny <= m && a[nx][ny] != '#'){
if(now + 1 < dist[nx][ny]){
dist[nx][ny] = now + 1;
q.push_back({nx, ny});
}
}
}
}
}
}
int main(){
ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
cin >> n >> m >> sx >> sy >> ex >> ey;
for(int i = 1; i <= n; i++){
for(int j = 1; j <= m; j++){
cin >> a[i][j];
}
}
memset(dist, 127, sizeof(dist));
bfs();
if(dist[ex][ey] < 1 << 30)cout << dist[ex][ey];
else cout << -1;
return 0;
}